Chapter 4: Laws of Motion
1. Force and Inertia
- Force: Push or pull that changes state of motion
- Inertia: Resistance to change in motion
- Greater mass → greater inertia
2. Newton’s First Law
A body remains at rest or in uniform motion unless acted upon by an external force.
- Also called Law of Inertia
3. Momentum and Newton’s Second Law
- Momentum (p): p = mv
- Newton’s Second Law: Force = rate of change of momentum
F = ma
4. Impulse
Impulse is change in momentum.
Impulse = F × t = Change in Momentum
5. Newton’s Third Law
For every action, there is an equal and opposite reaction.
6. Law of Conservation of Momentum
Total momentum before collision = total momentum after collision
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
7. Equilibrium of Forces
- Net force = 0
- Body remains at rest or moves uniformly
8. Friction
Types
- Static friction
- Kinetic friction
- Rolling friction
Laws of Friction
- Friction ∝ Normal reaction
- Independent of area of contact
F = μN
Lubrication: Reduces friction
9. Uniform Circular Motion
- Velocity changes direction continuously
- Centripetal force acts toward center
F = mv²/r
10. Banking of Roads
- Vehicles move safely on curves due to centripetal force
- Banked roads reduce dependence on friction
11. MCQ One-Liners
- Inertia depends on mass.
- Unit of force is Newton.
- Momentum = mass × velocity.
- SI unit of momentum is kg·m/s.
- Force = ma.
- Impulse equals change in momentum.
- Action-reaction forces act on different bodies.
- Momentum is conserved in isolated system.
- Static friction is greater than kinetic friction.
- Rolling friction is minimum.
- Friction depends on normal reaction.
- Lubricants reduce friction.
- Centripetal force acts toward center.
- Unit of friction is Newton.
- Equilibrium means net force zero.
- Acceleration is zero in equilibrium.
- Friction opposes motion.
- Banking reduces need for friction.
- Impulse unit is N·s.
- Force changes momentum.
12. Numerical Problems with Solutions
1. Force Calculation
m = 5 kg, a = 2 m/s²
F = ma = 5×2 = 10 N
2. Momentum
m = 10 kg, v = 3 m/s
p = mv = 10×3 = 30 kg·m/s
3. Impulse
F = 20 N, t = 5 s
Impulse = 20×5 = 100 Ns
4. Friction Force
μ = 0.5, N = 10 N
F = μN = 0.5×10 = 5 N
5. Conservation of Momentum
m₁=2kg,u₁=3m/s; m₂=1kg,u₂=0
Initial momentum = 2×3 = 6
After collision:
6 = 2v₁ + v₂
After collision:
6 = 2v₁ + v₂
6. Centripetal Force
m = 2 kg, v = 4 m/s, r = 2 m
F = mv²/r = 2×16/2 = 16 N
7. Acceleration
F = 20 N, m = 4 kg
a = F/m = 20/4 = 5 m/s²
8. Normal Reaction
m = 10 kg, g = 10
N = mg = 10×10 = 100 N